Step 1: Identify given values
In an arithmetic progression (A.P.), the sum of the first \( n \) terms is given by:
\[
S_n = \frac{n}{2} [2a + (n-1)d]
\]
where:
- First term \( a = 2 \)
- Common difference \( d = 4 - 2 = 2 \)
- Number of terms \( n = 50 \)
Step 2: Compute the sum
\[
S_{50} = \frac{50}{2} [2(2) + (50-1) \times 2]
\]
\[
= 25 [4 + 49 \times 2]
\]
\[
= 25 [4 + 98]
\]
\[
= 25 \times 102
\]
\[
= 2550
\]
Thus, the correct answer is \( 2550 \).