First term: \( a = 1 \), Common difference: \( d = 3 - 1 = 2 \), Number of terms: \( n = 30 \).
Using the sum formula for an A.P.:
\[
S_n = \frac{n}{2} (2a + (n-1) d)
\]
\[
S_{30} = \frac{30}{2} \times (2(1) + (30-1) (2))
\]
\[
= 15 \times (2 + 58)
\]
\[
= 15 \times 60 = 900.
\]