To solve this problem, we need to determine the number of sigma ($\sigma$) and pi ($\pi$) bonds in the given structure of Hex-1,3-dien-5-yne, which is $CH_2=CH-CH=CH-CH_2-C \equiv CH$.
1. Analyzing the Structure:
We need to count each $\sigma$ and $\pi$ bond in the molecule.
2. Counting Sigma Bonds:
Total $\sigma$ bonds = 1 + 1 + 1 + 1 + 2 + 1 + 1 + 2 + 1 = 11
3. Counting Pi Bonds:
Total $\pi$ bonds = 1 + 1 + 2 = 4
4. Calculating the Sum:
Sum of $\sigma$ and $\pi$ bonds = 11 + 4 = 15
Final Answer:
The sum of sigma ($\sigma$) and pi ($\pi$) bonds is 15.
Hex-1,3-dien-5-yne is a hydrocarbon with 6 carbon atoms (hex- means 6). The name gives us key information:
The carbon chain is linear with the following bonds:
The structural formula is: H₂C=CH-CH=CH-C≡CH.
Sigma (σ) bonds are the single covalent bonds between atoms. In organic molecules:
Let’s count the σ bonds in H₂C=CH-CH=CH-C≡CH:
Carbon-carbon bonds:
Total C-C σ bonds = 5.
Carbon-hydrogen bonds:
Total C-H σ bonds = 2 + 1 + 1 + 1 + 1 = 6.
Total σ bonds = 5 (C-C) + 6 (C-H) = 11.
Pi (π) bonds are the additional bonds in double and triple bonds:
Let’s count the π bonds in the molecule:
Total π bonds = 1 + 1 + 2 = 4.
Now, add the number of σ Favored and π bonds:
σ bonds = 11
π bonds = 4
Sum = 11 + 4 = 15.
The sum of sigma (σ) and pi (π) bonds in hex-1,3-dien-5-yne is 15
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The reaction : \(A_2 \rightleftharpoons 2A\)

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What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)