Concept:
In age-related problems involving ratios from a different time period, it is often easiest to calculate the sum of ages for that specific time period first. If the present sum is \(S\), the sum \(n\) years ago for \(k\) people is \(S - (n \times k)\).
Step 1: Calculate the sum of ages 5 years ago.
Present sum = 75 years.
Number of people = 3 (Anish, Ajay, Anvit).
Sum 5 years ago = \(75 - (3 \times 5) = 75 - 15 = 60 \text{ years}\).
Step 2: Use the ratio to find Ajay's age 5 years ago.
The ratio 5 years ago was \(3 : 4 : 5\).
Sum of ratio parts = \(3 + 4 + 5 = 12\).
Ajay's share 5 years ago = \(\frac{4}{12} \times 60 = \frac{1}{3} \times 60 = 20 \text{ years}\).
Step 3: Find Ajay's present age.
Present age = Age 5 years ago + 5
Present age = \(20 + 5 = 25 \text{ years}\).