
Equation of tangent to the parabola at
P(\(\frac{8}{5},\frac{6}{5}\))
75x⋅85=160(y+\(\frac{6}{5}\))−192
⇒ 120x = 160y
⇒ 3x = 4y
The equation of the circle touching the given parabola at P can be taken as
(x−\(\frac{8}{5}\))2+(y−\(\frac{6}{5}\))2+λ(3x−4y)=0
If this circle touches the y-axis then
\(\frac{64}{25}\)+(y−65)2+λ(−4y)=0
⇒y2−2y(2λ+65)+4=0
⇒ D = 0
⇒(\(\frac{2λ+6}{6}\))2=4
⇒λ=\(\frac{2}{5}\) or −\(\frac{8}{5}\)
Radius = 1 or 4
Sum of diameter = 10
If the shortest distance of the parabola \(y^{2}=4x\) from the centre of the circle \(x² + y² - 4x - 16y + 64 = 0\) is d, then d2 is equal to:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).

=> MP2 = PS2
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2