The suitable method that can be used for separation of products \(X\) and \(Y\) is: \[ {C6H6 →[CH3Cl/Anhyd. AlCl3] X →[dil. HNO3/H2SO4] X + Y} \]
The suitable method that can be used for separation of products \(X\) and \(Y\) is: \[ {C6H6 →[CH3Cl/Anhyd. AlCl3] X →[dil. HNO3/H2SO4] X + Y} \]
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- Sublimation
- Differential extraction
- Continuous extraction
- Fractional distillation
The Correct Option is D
Solution and Explanation
Step 1: Identify the first reaction.
Benzene reacts with methyl chloride in presence of anhydrous aluminium chloride.
This is Friedel–Crafts alkylation. $$ C_6H_6 + CH_3Cl \xrightarrow{AlCl_3} C_6H_5CH_3 + HCl $$ The product is toluene.
Step 2: Identify nitration of toluene.
Toluene undergoes nitration in presence of dilute nitric acid and sulphuric acid: $$ dil.\ HNO_3 / H_2SO_4 $$ The methyl group is an ortho–para directing group.
So nitration gives mainly:
o-nitrotoluene and p-nitrotoluene
Step 3: Separation of the two products.
The ortho and para isomers have different boiling points.
Hence, they can be separated by fractional distillation.
Step 4: Final conclusion.
The suitable method for separation is:
Fractional distillation
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