Question:

The substituent X increases electron density in benzene ring by hyperconjugation effect and substituent Y decreases electron density in benzene by resonance effect. X and Y respectively are

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\[ -CH_3 \] is activating due to hyperconjugation. \[ -NO_2 \] is strongly deactivating due to the $-R$ effect.
Updated On: Jun 17, 2026
  • $-CH_3,\ -NO_2$
  • $-OCH_3,\ -COCH_3$
  • $-OH,\ -NO_2$
  • $-CH_3,\ -NHCH_3$
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The Correct Option is A

Solution and Explanation

Concept: Hyperconjugation increases electron density in aromatic rings through sigma-electron delocalization. Electron withdrawing groups decrease electron density through negative resonance effect ($-R$ effect).

Step 1:
Identify the group showing hyperconjugation.
Alkyl groups such as \[ -CH_3 \] donate electron density to the benzene ring through hyperconjugation. Therefore X must be \[ -CH_3 \]

Step 2:
Identify the group showing negative resonance effect.
The nitro group \[ -NO_2 \] withdraws electrons strongly through resonance. Hence it decreases electron density in the benzene ring. Therefore Y must be \[ -NO_2 \]

Step 3:
Choose the answer.
\[ \boxed{-CH_3,\ -NO_2} \]
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