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The strength of an acid is determined by the stability of its conjugate base.
Electron-withdrawing groups (-I and -M effects) stabilize the conjugate base by delocalizing the negative charge after the loss of \( \text{H}^+ \). Electron-donating groups (+I and +M effects) destabilize the conjugate base.
In the given options, all are substituted phenols. The substituents are:
Since the nitro group (\( \text{-NO}_2 \)) has the strongest electron-withdrawing effect (-I and -M), it stabilizes the conjugate base of the phenol most effectively. Therefore, the compound with the \( \text{-NO}_2 \) substituent (option 4) is the strongest acid among the given options.

The acid strength of a phenolic compound depends on the electron-withdrawing or electron-donating groups attached to the benzene ring. The electron-withdrawing group increases the acidity of the compound. Among the options, the nitro group (-NO\(_2\)) is a strong electron-withdrawing group through the inductive effect (-I), making the compound with -NO\(_2\) attached to the ring the most acidic.
Two positively charged particles \(m_1\) and \(m_2\) have been accelerated across the same potential difference of 200 keV. Given mass of \(m_1 = 1 \,\text{amu}\) and \(m_2 = 4 \,\text{amu}\). The de Broglie wavelength of \(m_1\) will be \(x\) times that of \(m_2\). The value of \(x\) is _______ (nearest integer). 