The steam volatile compounds among the following are:

To solve this problem, we need to understand the relationship between steam volatility, intermolecular forces (especially hydrogen bonding), and molecular structure.
1. Understanding Steam Volatility:
Steam volatile compounds can be distilled using steam distillation, meaning they vaporize readily in the presence of steam. This is favored by lower boiling points and weaker intermolecular forces.
2. The Role of Hydrogen Bonding:
Intramolecular hydrogen bonds (within a molecule) increase volatility because they reduce the molecule's ability to form strong intermolecular interactions. Intermolecular hydrogen bonds (between molecules) decrease volatility by increasing the strength of the interactions between molecules.
3. Identifying Key Factors:
The key factor determining steam volatility in this context is the presence of intramolecular hydrogen bonds. Molecules with these bonds are more volatile due to reduced intermolecular attraction.
4. Conclusion:
Molecules with intramolecular hydrogen bonds are more likely to be steam volatile.
Final Answer:
Molecules with intramolecular hydrogen bonds are more likely to be steam volatile are A and B
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)