Concept:
The steady-state error ($e_{ss}$) evaluates a control system's tracking accuracy as time approaches infinity ($t \rightarrow \infty$). It depends on the input signal type (position, velocity, acceleration) and the System Type, which is defined by the number of open-loop poles located exactly at the origin ($s = 0$) of the complex s-plane.
Step 1: Identify the input signal and its Laplace domain form.
The input provided is a standard unit velocity input (also known as a unit ramp function, $r(t) = t$). Its Laplace transform is:
\[
R(s) = \frac{1}{s^2}
\]
Step 2: Set up the steady-state error formula.
Using the Final Value Theorem for a unity feedback control system:
\[
e_{ss} = \lim_{s \to 0} \frac{s \cdot R(s)}{1 + G(s)H(s)} = \lim_{s \to 0} \frac{s \cdot \left(\frac{1}{s^2}\right)}{1 + G(s)H(s)} = \lim_{s \to 0} \frac{1}{s + s \cdot G(s)H(s)}
\]
Step 3: Account for a Type-2 system configuration.
A Type-2 system contains exactly two pure integrators at the origin. Its open-loop transfer function can be written as:
\[
G(s)H(s) = \frac{K \prod (s + z_i)}{s^2 \prod (s + p_i)}
\]
Substituting this expression into the error equation yields:
\[
e_{ss} = \lim_{s \to 0} \frac{1}{s + s \cdot \left[ \frac{K \prod (s + z_i)}{s^2 \prod (s + p_i)} \right]} = \lim_{s \to 0} \frac{1}{s + \frac{K \prod (s + z_i)}{s \prod (s + p_i)}}
\]
Evaluating the limit as $s \to 0$:
\[
e_{ss} = \frac{1}{0 + \frac{K \cdot \text{constant}}{0}} = \frac{1}{\infty} = 0
\]
Because a Type-2 system has high open-loop loop gain at low frequencies, it can track a ramp velocity input with zero steady-state tracking error. This corresponds to Option (D).