Question

The standard sutureless cataract surgery done with phacoemulsification and a foldable IOL has an incision of:

• A. 1 mm - 1.5 mm
• B. 2 mm - 2.5 mm
• C. 3 mm - 3.5 mm
• D. 3.5 mm - 4 mm

Hint:

A foldable IOL lets phaco use a small, self sealing corneal wound, about 2 to 2.5 mm.

Answer 1

The Correct Option is B

Step 1: Recall what sutureless phacoemulsification means.
In phacoemulsification, the surgeon breaks up the cloudy lens with an ultrasound probe and removes the pieces through a small opening in the cornea. The wound is made small enough that it seals on its own, without a stitch.

Step 2: Know the incision size that allows a self sealing wound.
A clear corneal incision of about 2 mm to 2.5 mm gives enough room for the phaco probe and its irrigation sleeve to work, and it also lets a foldable intraocular lens (IOL) pass through, rolled up, using an injector. A wound this size closes on its own because of the way the layers of the cornea form a valve at that width.

Step 3: Rule out the other sizes.
An incision of 1 mm to 1.5 mm is too narrow for the standard phaco probe and sleeve to fit and move safely; that range belongs to special micro incision setups, not the routine surgery. Incisions of 3 mm to 3.5 mm or 3.5 mm to 4 mm are wider than needed once foldable lenses became available, and a bigger wound adds more surgically induced astigmatism.

Step 4: Final Answer.
The standard sutureless phacoemulsification incision used with a foldable IOL is 2 mm to 2.5 mm. \[ \boxed{\text{2 mm to 2.5 mm}} \]