The spin-only magnetic moment value of \(\mathrm{B_2^+}\) species is _____________ \(\times 10^{-2}\) BM. (Nearest integer)
[Given : \(\sqrt{3} = 1.73\)]
[Given : \(\sqrt{3} = 1.73\)]
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Correct Answer: 173
Solution and Explanation
Step 2: For \(\mathrm{B_2}\) the \(\pi_{2p}\) orbitals lie below \(\sigma_{2p_z}\). Configuration of \(\mathrm{B_2^+}\): \(\sigma 1s^2\, \sigma^* 1s^2\, \sigma 2s^2\, \sigma^* 2s^2\, \pi 2p_x^1\) (9 electrons).
Step 3: Number of unpaired electrons n = 1.
Step 4: \(\mu = \sqrt{n(n+2)} = \sqrt{1\times 3} = \sqrt{3} = 1.73\) BM = \(173 \times 10^{-2}\) BM.
Answer: 173
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