\(CoCl_3⋅4NH_3 \xrightarrow{\text {excess} \ AgNO_3 } [Co(NH_3)_4⋅Cl_2]+AgCl\)
\(NiCl_2⋅6H_2O\xrightarrow{\text {excess} \ AgNO_3 }[Ni(H_2O)_6]_2+ +2AgCl\)
\(PtCl_4⋅2HCl→[PtCl_6]^{4−} + \text {No AgCl ppt}\)
\([Ni^{2+}(H_2O)_6]=d^8=t_2g^6 e^2_g=2\) unpaired~electrons
Magnetic moment,
\(=\sqrt {2(2+2)}\)
\(=\sqrt 8\)
\(≈3\)
So, the answer is \(3\).
Given below are two statements:
Statement I: The number of species among \( SF_4 \), \( NH_4^+ \), \( [NiCl_4]^{2-} \), \( XeF_4 \), \( [PtCl_4]^{2-} \), \( SeF_4 \) and \( [Ni(CN)_4]^{2-} \), that have tetrahedral geometry is 3.
Statement II: In the set \( [NO_2] \), \( BeH_2 \), \( BF_3 \), \( AlCl_3 \), all the molecules have incomplete octet around the central atom.
In the light of the above statements, choose the correct answer from the options given below:
\[ \left( \frac{1}{{}^{15}C_0} + \frac{1}{{}^{15}C_1} \right) \left( \frac{1}{{}^{15}C_1} + \frac{1}{{}^{15}C_2} \right) \cdots \left( \frac{1}{{}^{15}C_{12}} + \frac{1}{{}^{15}C_{13}} \right) = \frac{\alpha^{13}}{{}^{14}C_0 \, {}^{14}C_1 \cdots {}^{14}C_{12}} \]
Then \[ 30\alpha = \underline{\hspace{1cm}} \]


A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.