The specific gravity of a soil is 2.60. The soil is at 50% degree of saturation with a water content of 15%. The void ratio of the soil is
Step 1: Write known values.
$w = 0.15$ (15%)
$S = 0.50$ (50%)
$G = 2.60$
Step 2: Substitute values in formula.
\[
0.15 = \frac{0.50 \cdot e}{2.60}
\]
Step 3: Solve for $e$.
\[
e = \frac{0.15 \times 2.60}{0.50}
\]
\[
e = \frac{0.39}{0.50} = 0.78
\]
Final Answer:
\[
\boxed{0.78}
\]