Question:

The species that can have a trans-isomer is :
(en = ehane-1, 2-diamine, ox = oxalate)

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Trans isomers need two monodentate ligands that can sit opposite each other; bidentate ligands span cis positions only.
Updated On: Nov 5, 2026
  • \([\mathrm{Cr(en)_2(ox)}]^{+}\)
  • \([\mathrm{Pt(en)Cl_2}]\)
  • \([\mathrm{Pt(en)_2Cl_2}]^{2+}\)
  • \([\mathrm{Zn(en)Cl_2}]\)
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The Correct Option is C

Solution and Explanation

(1) \([\mathrm{Cr(en)_2(ox)}]^+\): octahedral, all three ligands bidentate (each spans cis positions only), so only cis (optical) isomers, no trans.
(2) \([\mathrm{Pt(en)Cl_2}]\): Pt(II) square planar with one bidentate en, so the two Cl are forced cis; no trans.
(3) \([\mathrm{Pt(en)_2Cl_2}]^{2+}\): octahedral type \(\mathrm{M(AA)_2X_2}\): the two Cl can be cis or trans. It has a trans isomer.
(4) \([\mathrm{Zn(en)Cl_2}]\): tetrahedral, no cis-trans isomerism.
Answer: (3) [Pt(en)2Cl2]2+
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