The set in which compounds have different nature is :
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- \(\mathrm{B(OH)_3}\) and \(\mathrm{H_3PO_3}\)
- \(\mathrm{B(OH)_3}\) and \(\mathrm{Al(OH)_3}\)
- \(\mathrm{NaOH}\) and \(\mathrm{Ca(OH)_2}\)
- \(\mathrm{Be(OH)_2}\) and \(\mathrm{Al(OH)_3}\)
The Correct Option is B
Solution and Explanation
(2) \(\mathrm{B(OH)_3}\) is acidic, whereas \(\mathrm{Al(OH)_3}\) is amphoteric (dissolves in both acid and alkali). Different nature.
(3) \(\mathrm{NaOH}\) and \(\mathrm{Ca(OH)_2}\) are both strongly basic, same nature.
(4) \(\mathrm{Be(OH)_2}\) and \(\mathrm{Al(OH)_3}\) are both amphoteric, same nature (diagonal relationship).
Hence the set with different nature is (2).
Answer: (2) \(\mathrm{B(OH)_3}\) and \(\mathrm{Al(OH)_3}\)
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