Question:

The set having ions which are coloured and paramagnetic both is :

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Coloured requires partly filled d-orbitals (d1 to d9) and paramagnetic requires unpaired electrons; d0 and d10 ions are colourless and diamagnetic.
Updated On: Nov 4, 2026
  • \(\mathrm{Cu^{2+}, Cr^{3+}, Sc^{+}}\)
  • \(\mathrm{Cu^{2+}, Zn^{2+}, Mn^{4+}}\)
  • \(\mathrm{Sc^{3+}, V^{5+}, Ti^{4+}}\)
  • \(\mathrm{Ni^{2+}, Mn^{7+}, Hg^{2+}}\)
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The Correct Option is A

Solution and Explanation

Option 1: \(\mathrm{Cu^{2+}}\) (3d9, 1 unpaired e-), \(\mathrm{Cr^{3+}}\) (3d3, 3 unpaired), \(\mathrm{Sc^{+}}\) ([Ar]3d1 4s1, 2 unpaired): all have unpaired electrons in partly filled d-subshell, so coloured and paramagnetic.
Option 2: \(\mathrm{Zn^{2+}}\) is 3d10, colourless and diamagnetic. Option 3: \(\mathrm{Sc^{3+}, V^{5+}, Ti^{4+}}\) are all d0, colourless. Option 4: \(\mathrm{Mn^{7+}}\) (d0) and \(\mathrm{Hg^{2+}}\) (d10) are colourless.
Answer: (1) \(\mathrm{Cu^{2+}, Cr^{3+}, Sc^{+}}\)
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