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the roots of the quadratic equation px 2 qx r 0 p
Question:
The roots of the quadratic equation \( px^2 - qx + r = 0, \, p \neq 0 \) are:
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The quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] is used to find roots of any quadratic equation.
Bihar Board X - 2024
Bihar Board X
Updated On:
Oct 27, 2025
\( \frac{q \pm \sqrt{q^2 - 4pr}}{2p} \)
\( \frac{q \pm \sqrt{q^2 + 4pr}}{2p} \)
\( \frac{-q \pm \sqrt{q^2 - 4pr}}{2p} \)
\( \frac{-q \pm \sqrt{q^2 + 4pr}}{2p} \)
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The Correct Option is
C
Solution and Explanation
Using the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] For \( px^2 - qx + r = 0 \): \[ x = \frac{-(-q) \pm \sqrt{(-q)^2 - 4(p)(r)}}{2p} \] \[ x = \frac{q \pm \sqrt{q^2 - 4pr}}{2p} \]
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