The figure shows five root-locus branches emerging from a single real pole located at $s = -1$. The angles between adjacent branches are exactly:
\[
\frac{360^\circ}{5} = 72^\circ,
\]
which matches the diagram showing rays at $36^\circ$, $108^\circ$, $180^\circ$, $252^\circ$, and $324^\circ$ relative to the real axis.
This pattern is characteristic of a 5th-order real pole, i.e., a pole of multiplicity 5.
Thus, the forward path transfer function must have the form:
\[
G(s) = \frac{1}{(s + 1)^5},
\]
so that the characteristic equation
\[
1 + K G(s) = 0
\]
produces 5 equally spaced root-locus angles around $s = -1$.
None of the other options give a 5th-order pole at $s = -1$ or match the 72° symmetry.
Hence, the correct choice is option (A).
Final Answer: $\dfrac{1}{(s + 1)^5}$