The resistors in the circuits below each represent a light bulb. If all three circuits use the same size battery, which circuit will produce the most light?
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The circuit with the lowest resistance will produce the most light as it dissipates the most power.
I, II, and III will produce the same amount of light
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The Correct Option isA
Solution and Explanation
The power dissipated in a resistor (which corresponds to the brightness of the light bulb) is given by:
\[
P = \frac{V^2}{R}
\]
where:
$V$ is the voltage (which is the same for all circuits), and
$R$ is the resistance of the circuit.
In circuit I, the resistance is the lowest, so it will produce the most power and thus the most light.
