Question

The resistance of the conductor is \( \sqrt{3}\Omega \) the angle made by the V-I graph with the voltage axis is \( \theta \)

• A. \( \theta = 60^\circ \)
• B. \( \theta = 30^\circ \)
• C. \( \theta = 15^\circ \)
• D. \( \theta = 45^\circ \)

Hint:

Slope in V-I graph is resistance. Always check which axis angle is measured from.

Answer 1

The Correct Option is B

Step 1: Understand V-I graph.
In V-I graph, slope represents resistance:
\[ R = \frac{V}{I} \]

Step 2: Relation of slope with angle.
Slope of graph = \( \tan\theta \) where \( \theta \) is angle with current axis.

Step 3: But given angle is with voltage axis.
If angle with current axis is \( \alpha \), then:
\[ \theta = 90^\circ - \alpha \]

Step 4: Write slope relation.
\[ \tan\alpha = R = \sqrt{3} \]

Step 5: Find angle \( \alpha \).
\[ \alpha = 60^\circ \]

Step 6: Convert to required angle.
\[ \theta = 90^\circ - 60^\circ = 30^\circ \]

Step 7: Final Answer.
\[ \boxed{30^\circ} \]