The reaction that produces o-bromophenol as the major product is 
Step 1: Understand bromination of phenols.
Phenols are strongly activating and \emph{o,p}-directing. When bromination is carried out in a non-aqueous solvent such as CS$_2$ at low temperature, monobromination occurs predominantly at the ortho position.
Step 2: Evaluate the options.
(A) and (B) involve conditions that lead to rearrangements or decomposition, not selective ortho bromination.
(D) involves benzyne formation and substitution at unpredictable positions.
(C) Br$_2$/CS$_2$ at 0 °C specifically gives ortho-bromophenol as the major product because para attack is sterically hindered.
Step 3: Conclusion.
Thus, option (C) produces o-bromophenol as the major product.
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

