The reaction \(\mathrm{X} \to \mathrm{Y}\) is an exothermic reaction. Activation energy of the reaction for X into Y is 150 kJ mol-1. Enthalpy of reaction is 135 kJ mol-1. The activation energy for the reverse reaction, \(\mathrm{Y} \to \mathrm{X}\) will be :
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- 280 kJ mol-1
- 285 kJ mol-1
- 270 kJ mol-1
- 15 kJ mol-1
The Correct Option is B
Solution and Explanation
The reaction is exothermic, so the magnitude of the enthalpy change is 135 kJ mol-1 and \(\Delta H = -135\) kJ mol-1.
\(E_{a,b} = E_{a,f} - \Delta H = 150 - (-135) = 285\) kJ mol-1.
Answer: (2) 285 kJ mol-1
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