Question

The ratio of volume of \( \text{Al}^{27} \) nucleus to its surface area is (Given \( R_0 = 1.2 \times 10^{-15} \) m)

• A. \( 2.1 \times 10^{-15} \)
• B. \( 1.3 \times 10^{-15} \)
• C. \( 0.22 \times 10^{-15} \)
• D. \( 1.2 \times 10^{-15} \)

Answer 1

The Correct Option is D

The volume of a nucleus is proportional to \( R^3 \) and the surface area is proportional to \( R^2 \).
Therefore, the ratio of volume to surface area is proportional to \( R \), which gives:
\(\ \frac{V}{A} = R_0 \approx 1.2 \times 10^{-15} \, \text{m}\)