The pseudocode provided is an implementation of Bubble Sort. Let’s analyze the number of swap operations in the case where the array is initially sorted in descending order:
The outer loop runs from \( i = 0 \) to \( n-2 \), where \( n = 30 \). Therefore, the outer loop runs \( 29 \) times.
The inner loop runs from \( j = 0 \) to \( n-i-2 \), which means the number of iterations decreases as \( i \) increases.
For each value of \( i \), the number of comparisons in the inner loop is:
\[
n - i - 2
\]
Thus, the total number of comparisons (and therefore the number of potential swaps) is the sum of the number of comparisons for each value of \( i \) from 0 to \( n-2 \).
Step 1: Total Number of Comparisons
The number of comparisons for each value of \( i \) is:
For \( i = 0 \), the inner loop runs \( n-1 \) times.
For \( i = 1 \), the inner loop runs \( n-2 \) times.
For \( i = 2 \), the inner loop runs \( n-3 \) times.
...
For \( i = n-2 \), the inner loop runs 1 time.
Thus, the total number of comparisons is the sum of the first \( n-1 \) integers:
\[
{Total comparisons} = (n-1) + (n-2) + \ldots + 1 = \frac{n(n-1)}{2}
\]
For \( n = 30 \):
\[
{Total comparisons} = \frac{30 \times 29}{2} = 435
\]
Step 2: Number of Swaps
In a Bubble Sort, a swap occurs every time a comparison finds that \( A[j]>A[j+1] \). Since the array is initially sorted in descending order, every comparison will result in a swap.
Thus, the number of swaps is equal to the total number of comparisons, which is 435.
Therefore, the number of swap operations performed is 435.