Question

The product formed in the first step of the reaction of $CH_3 - CH_2 - CH(Br) - CH_2 - CH(Br) - CH_3$ with excess $Mg/Et_2O$ is :

• A. A
• B. B
• C. C
• D. D

Hint:

Grignard reagents are highly reactive organometallic compounds. "Excess" usually indicates that all functional groups capable of reacting will do so.

Answer 1

The Correct Option is A

Step 1: Magnesium reacts with alkyl halides in dry ether to form Grignard reagents ($R-MgX$).
Step 2: Since there are two bromine atoms and "excess" Magnesium is used, both bromine sites will react.
Step 3: The resulting product will have two $-MgBr$ groups attached to the carbon chain.