The product B formed in the following reaction sequence is:
\[
{C}_6{H}_5{CN} \xrightarrow{{HCl}} (A) \xrightarrow{{AgCN}} (B)
\]
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The Correct Option is C
Solution and Explanation
To identify the product B formed in the given reaction sequence, we need to analyze each step:
- First Step: Hydrolysis of Benzonitrile
The starting compound is benzonitrile, \({C}_6{H}_5{CN}\). When benzonitrile undergoes hydrolysis in the presence of hydrochloric acid (HCl), it converts to the corresponding amide, benzamide (\({C}_6{H}_5{CONH}_2\)). This transformation is depicted in the reaction below:
\[ {C}_6{H}_5{CN} + 2H_2O + HCl \rightarrow {C}_6{H}_5{CONH}_2 + NH_4Cl \]
- Second Step: Reaction with Silver Cyanide
The benzamide product (A) is then reacted with silver cyanide (AgCN). In this step, a nucleophilic substitution takes place where the amide group is converted to the isocyanate group, forming phenyl isocyanate (\({C}_6{H}_5{NCO}\)). The reaction can be summarized as follows:
\[ {C}_6{H}_5{CONH}_2 + AgCN \rightarrow {C}_6{H}_5{NCO} + Ag \]
The final product B is phenyl isocyanate (\({C}_6{H}_5{NCO}\)).
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