The price of a chocolate is increased by \( x% \) and then reduced by \( x% \). The new price is 96.76% of the original price. Then \( x \) is:
\[ P + \frac{x}{100}P = P \left(1 + \frac{x}{100}\right) \]
\[ P \left(1 + \frac{x}{100}\right) \left(1 - \frac{x}{100}\right) = 0.9676P \]
\[ \left(1 + \frac{x}{100}\right) \left(1 - \frac{x}{100}\right) = 0.9676 \]
\[ \left(1 + \frac{x}{100}\right) \left(1 - \frac{x}{100}\right) = 1 - \left(\frac{x}{100}\right)^2 \]
\[ 1 - \left(\frac{x}{100}\right)^2 = 0.9676 \]
\[ \left(\frac{x}{100}\right)^2 = 1 - 0.9676 = 0.0324 \]
\[ \frac{x}{100} = \sqrt{0.0324} = 0.18 \]
\[ x = 0.18 \times 100 = 18 \]
Answer: \( x = 18 \)
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