Question:
The population of a town increased from 1,50,000 to 2,24,500 in 11 years. The average percentage increase of population per year is:
The population of a town increased from 1,50,000 to 2,24,500 in 11 years. The average percentage increase of population per year is:
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For "average percentage increase", use the simple arithmetic mean formula: \( \frac{\text{Total % Growth}}{\text{Years}} \), unless "Compound Annual Growth Rate" (CAGR) is explicitly requested.
Updated On: Feb 17, 2026
- 8.75%
- 4.54%
- 4.37%
- 4.52%
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The Correct Option is D
Solution and Explanation
Step 1: Calculate Total Increase:
Initial Population = 1,50,000 Final Population = 2,24,500 Increase = \( 2,24,500 - 1,50,000 = 74,500 \). Step 2: Calculate Total Percentage Increase:
\[ \text{Total %} = \frac{74,500}{1,50,000} \times 100 \] \[ \text{Total %} = \frac{745}{15} = \frac{149}{3} \approx 49.666% \] Step 3: Calculate Average Annual Increase:
\[ \text{Average %} = \frac{\text{Total %}}{\text{Number of Years}} = \frac{49.666}{11} \] \[ \text{Average %} \approx 4.515% \] Rounding to two decimal places gives 4.52%.
Initial Population = 1,50,000 Final Population = 2,24,500 Increase = \( 2,24,500 - 1,50,000 = 74,500 \). Step 2: Calculate Total Percentage Increase:
\[ \text{Total %} = \frac{74,500}{1,50,000} \times 100 \] \[ \text{Total %} = \frac{745}{15} = \frac{149}{3} \approx 49.666% \] Step 3: Calculate Average Annual Increase:
\[ \text{Average %} = \frac{\text{Total %}}{\text{Number of Years}} = \frac{49.666}{11} \] \[ \text{Average %} \approx 4.515% \] Rounding to two decimal places gives 4.52%.
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