Let the required point be \( (0, y) \) on the y-axis.
The distances from \( (0, y) \) to \( (5, -2) \) and \( (0, y) \) to \( (-3, 2) \) should be equal.
Using the distance formula for each point, we have two equations:
\[
\sqrt{(5 - 0)^2 + (-2 - y)^2} = \sqrt{(-3 - 0)^2 + (2 - y)^2}
\]
Squaring both sides and solving for \( y \), we get \( y = 3 \).
Therefore, the point is \( (0, 3) \).