Question

The pH of pure water at 25\(^\circ\)C is:

• A. 0
• B. 5
• C. 7
• D. 14

Hint:

At 25\(^\circ\)C, neutral solutions always have pH = 7.

Answer 1

The Correct Option is C

Step 1: In pure water at 25\(^\circ\)C: \[ [\text{H}^+] = [\text{OH}^-] = 10^{-7}\,\text{M} \] Step 2: Calculate pH: \[ \text{pH} = -\log(10^{-7}) = 7 \] Hence, pure water is neutral.