Question:
The oxidation state of Mn in $KMnO_4$ is:
The oxidation state of Mn in $KMnO_4$ is:
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In $KMnO_{4}$, Mn is in its highest possible oxidation state (+7).
Updated On: May 4, 2026
- +7
- +6
- +5
- +4
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The Correct Option is A
Solution and Explanation
Step 1: Concept
The sum of oxidation states of all atoms in a neutral compound must equal zero.
Step 2: Meaning
We use standard oxidation numbers: Potassium (K) is +1 and Oxygen (O) is -2.
Step 3: Analysis
Let the oxidation state of Mn be $x$. The equation is: $(+1) + x + 4(-2) = 0$. This simplifies to: $1 + x - 8 = 0$, which means $x - 7 = 0$.
Step 4: Conclusion
Solving for $x$, we find that $x = +7$. Final Answer: (A)
The sum of oxidation states of all atoms in a neutral compound must equal zero.
Step 2: Meaning
We use standard oxidation numbers: Potassium (K) is +1 and Oxygen (O) is -2.
Step 3: Analysis
Let the oxidation state of Mn be $x$. The equation is: $(+1) + x + 4(-2) = 0$. This simplifies to: $1 + x - 8 = 0$, which means $x - 7 = 0$.
Step 4: Conclusion
Solving for $x$, we find that $x = +7$. Final Answer: (A)
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