In \(CrO_5\) (chromium pentoxide), the chromium atom is surrounded by peroxide groups (\(O_2^{2-}\)). To find the oxidation state of Cr, we consider the following:
- The peroxide group (\(O_2^{2-}\)) has an overall charge of -2.
- There are 5 peroxide groups, so their total charge is -10.
- To balance the charge, chromium must have an oxidation state of +6.
Thus, the oxidation number of Cr in \(CrO_5\) is +6.