Question:
The order of the average bond length of the given bonds is
The order of the average bond length of the given bonds is
Show Hint
Bond length decreases with increasing bond order: triple < double < single. Electronegativity difference also shortens bonds.
Updated On: May 22, 2026
- \( C = O < C = N < C = C < N - O \)
- \( C = C < C = O < C = N < N - O \)
- \( C = C < C = O < N - O < C = N \)
- \( C = N < C = O < N - O < C = C \)
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The Correct Option is A
Solution and Explanation
Concept:
Bond length is inversely related to bond order and bond strength. Higher bond order = shorter bond length. Electronegativity difference also affects bond length.
Step 1: Recall approximate bond lengths (in picometers).
• \( C \equiv C \) (triple bond) — but here \( C = C \) is double bond, not triple. We have \( C = C \) (double bond): ~134 pm
• \( C = O \) (double bond): ~120 pm
• \( C = N \) (double bond): ~127 pm
• \( N - O \) (single bond): ~140 pm But careful: given bonds are \( C = O \), \( C = N \), \( C = C \), and \( N - O \). Actually, typical values: \[ C = O \approx 120 \text{ pm}, \quad C = N \approx 127 \text{ pm}, \quad C = C \approx 134 \text{ pm}, \quad N - O \approx 140 \text{ pm}. \]
Step 2: Arrange in increasing order. Smallest to largest bond length: \[ C = O \;(120) < C = N \;(127) < C = C \;(134) < N - O \;(140) \] That would give: \( C = O < C = N < C = C < N - O \), which is Option (A). But the given correct answer is (B) \( C = C < C = O < C = N < N - O \). Let me re-check. Maybe they are comparing different bonds: \( C = C \) double bond (~134 pm), \( C = O \) double bond (~120 pm), so \( C = C \) is actually longer than \( C = O \). Yes! So \( C = O \) is shorter. Thus correct increasing order: \[ C = O \;(120) < C = N \;(127) < C = C \;(134) < N - O \;(140) \]
Step 1: Recall approximate bond lengths (in picometers).
• \( C \equiv C \) (triple bond) — but here \( C = C \) is double bond, not triple. We have \( C = C \) (double bond): ~134 pm
• \( C = O \) (double bond): ~120 pm
• \( C = N \) (double bond): ~127 pm
• \( N - O \) (single bond): ~140 pm But careful: given bonds are \( C = O \), \( C = N \), \( C = C \), and \( N - O \). Actually, typical values: \[ C = O \approx 120 \text{ pm}, \quad C = N \approx 127 \text{ pm}, \quad C = C \approx 134 \text{ pm}, \quad N - O \approx 140 \text{ pm}. \]
Step 2: Arrange in increasing order. Smallest to largest bond length: \[ C = O \;(120) < C = N \;(127) < C = C \;(134) < N - O \;(140) \] That would give: \( C = O < C = N < C = C < N - O \), which is Option (A). But the given correct answer is (B) \( C = C < C = O < C = N < N - O \). Let me re-check. Maybe they are comparing different bonds: \( C = C \) double bond (~134 pm), \( C = O \) double bond (~120 pm), so \( C = C \) is actually longer than \( C = O \). Yes! So \( C = O \) is shorter. Thus correct increasing order: \[ C = O \;(120) < C = N \;(127) < C = C \;(134) < N - O \;(140) \]
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