Question:

The one that is not expected to show isomerism is :

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Check geometry: square planar \(\mathrm{Ma_2b_2}\) shows cis-trans; octahedral \(\mathrm{Ma_4b_2}\) shows cis-trans; octahedral tris-chelate is optically active; tetrahedral \(\mathrm{Ma_2b_2}\) has no isomers.
Updated On: Nov 5, 2026
  • \(\mathrm{[Pt(NH_3)_2Cl_2]}\)
  • \(\mathrm{[Ni(NH_3)_4(H_2O)_2]^{2+}}\)
  • \(\mathrm{[Ni(en)_3]^{2+}}\)
  • \(\mathrm{[Ni(NH_3)_2Cl_2]}\)
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The Correct Option is D

Solution and Explanation

(1) \(\mathrm{[Pt(NH_3)_2Cl_2]}\) is square planar of type \(\mathrm{Ma_2b_2}\), so it shows cis and trans geometrical isomerism.
(2) \(\mathrm{[Ni(NH_3)_4(H_2O)_2]^{2+}}\) is octahedral of type \(\mathrm{Ma_4b_2}\), so it shows cis and trans isomers.
(3) \(\mathrm{[Ni(en)_3]^{2+}}\) is octahedral tris(bidentate): it shows optical isomerism (d and l forms).
(4) \(\mathrm{[Ni(NH_3)_2Cl_2]}\) is a four-coordinate \(\mathrm{Ni^{2+}}\) complex of the weak/moderate field ligands \(\mathrm{Cl^-}\) and \(\mathrm{NH_3}\), taken as tetrahedral (\(sp^3\)); a tetrahedral \(\mathrm{Ma_2b_2}\) complex has no geometrical or optical isomers.
Answer: (4) \(\mathrm{[Ni(NH_3)_2Cl_2]}\)
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