Question:

The number of possible optical isomers for the complexes MA2B2 with sp3 and dsp2 hydridized metal atom. respectively, is :
Note : A and B are unidentate netural and unidentate monoanionic ligands, respectively.

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Optical isomerism needs a chiral (non-superimposable on mirror image) structure; tetrahedral MA2B2 and square-planar MA2B2 both have mirror planes.
Updated On: Oct 31, 2026
  • 0 and 2
  • 0 and 0
  • 0 and 1
  • 2 and 2
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The Correct Option is B

Solution and Explanation

Step 1: sp3 hybridisation means a tetrahedral complex. In tetrahedral MA2B2 there is a mirror plane containing M, both A ligands (or both B), so it is achiral: 0 optical isomers.
Step 2: dsp2 hybridisation means a square-planar complex. The molecular plane is itself a mirror plane (and there are others), so every arrangement is achiral. The cis and trans forms are geometrical isomers only: 0 optical isomers.
Step 3: Hence the numbers are 0 and 0.
Answer: (B) 0 and 0
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