Step 1: Understand the fatty acid synthesis process.
The synthesis of palmitate (C16:0) from acetyl CoA occurs through the process of fatty acid synthesis, which involves the reduction of carbon-carbon bonds. For every two-carbon unit added, two NADPH molecules are required.
Step 2: Calculate the number of NADPH molecules required.
Palmitate (C16:0) is a 16-carbon fatty acid. To form palmitate, 8 two-carbon units are added. Each two-carbon unit requires 2 NADPH molecules for reduction, so the total number of NADPH molecules required is:
\[
8 \times 2 = 16 \, \text{NADPH}.
\]
Step 3: Conclusion.
Thus, 14 NADPH molecules are required for the synthesis of palmitate (C16:0) from acetyl CoA.
Which one of the following matches is CORRECT between the inhibitors given in Group A with their modes of action in Group B?
\[\begin{array}{|c|c|} \hline Group A & Group B \\ \hline \text{(P) Antimycin A} & \text{(i) Inhibits cytochrome c oxidase} \\ \hline \text{(Q) Amytal} & \text{(ii) Blocks electron transfer from cyt b to cyt c1} \\ \hline \text{(R) Carbon monoxide} & \text{(iii) Inhibits adenine nucleotide translocase} \\ \hline \text{(S) Atractyloside} & \text{(iv) Prevents electron transfer from Fe-S centers of complex 1 to ubiquinone} \\ \hline \end{array}\]