1. Male voters in city C = \( 12% \) of 40,000 = \( 4,800 \)
2. Male voters in city D = \( 26% \) of 40,000 = \( 10,400 \)
3. Percentage = \( \frac{4,800}{10,400} \times 100 = 18.46% \)
4. The closest available answer is **18%**.
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