The number of isomers possible for \(\mathrm{[Pt(en)(NO_2)_2]}\) is :
Show Hint
- 3
- 1
- 4
- 2
The Correct Option is A
Solution and Explanation
\(\mathrm{NO_2^-}\) is ambidentate (binds through N as nitro or through O as nitrito), giving linkage isomers:
(i) both through N: \(\mathrm{[Pt(en)(NO_2)_2]}\)
(ii) both through O: \(\mathrm{[Pt(en)(ONO)_2]}\)
(iii) one through N, one through O: \(\mathrm{[Pt(en)(NO_2)(ONO)]}\)
Total isomers = 3.
Answer: (1) 3
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