Question

The number of electrons present in 8 coulomb negative charge is:

• A. \( 5 \times 10^{19} \)
• B. \( 2.5 \times 10^{19} \)
• C. \( 12.8 \times 10^{19} \)
• D. \( 1.6 \times 10^{19} \)

Hint:

To find the number of electrons for a given charge, use: \[ N = \frac{Q}{e}, \] where \( Q \) is the total charge and \( e \) is the charge of a single electron (\( 1.6 \times 10^{-19} \, \text{C} \)).

Answer 1

The Correct Option is A

The charge of a single electron is \( e = 1.6 \times 10^{-19} \, \text{C} \). To find the number of electrons \( N \) in a charge \( Q = 8 \, \text{C} \), we use the formula: \[ N = \frac{Q}{e} = \frac{8}{1.6 \times 10^{-19}} = 5 \times 10^{19}. \] Thus, the number of electrons present in 8 coulomb of negative charge is \( 5 \times 10^{19} \).