Question:

The number of atoms per unit cell in FCC is

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In FCC, total atoms \(=8\times\frac{1}{8}+6\times\frac{1}{2}=4\).
  • \(4\)
  • \(2\)
  • \(1\)
  • \(6\)
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The Correct Option is A

Solution and Explanation

FCC means face centered cubic unit cell. In FCC, atoms are present at: \[ \text{8 corners} \] and \[ \text{6 face centers}. \] Each corner atom is shared by 8 unit cells. So contribution from corner atoms is: \[ 8\times \frac{1}{8}=1. \] Each face-centered atom is shared by 2 unit cells. So contribution from face-centered atoms is: \[ 6\times \frac{1}{2}=3. \] Therefore, total atoms per FCC unit cell: \[ 1+3=4. \] Hence, the number of atoms per unit cell in FCC is: \[ 4. \]
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