The molecule in which hybrid MOs involve only one d-orbital of the central atom is :
Show Hint
- \(\mathrm{XeF_4}\)
- \(\mathrm{[Ni(CN)_4]^{2-}}\)
- \(\mathrm{[CrF_6]^{3-}}\)
- \(\mathrm{BrF_5}\)
The Correct Option is B
Solution and Explanation
\(\mathrm{[Ni(CN)_4]^{2-}}\): Ni is +2 (\(3d^8\)); strong-field \(\mathrm{CN^-}\) pairs up the d electrons leaving one 3d orbital empty, giving square planar \(dsp^2\) hybridisation (one d-orbital).
\(\mathrm{[CrF_6]^{3-}}\): Cr3+ (\(3d^3\)) has two empty d-orbitals, \(d^2sp^3\) (two d-orbitals).
\(\mathrm{BrF_5}\): 5 bond pairs + 1 lone pair, \(sp^3d^2\) (two d-orbitals).
Only \(\mathrm{[Ni(CN)_4]^{2-}}\) uses a single d-orbital.
Answer: (2) \(\mathrm{[Ni(CN)_4]^{2-}}\)
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