The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is:
The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is:
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Solution and Explanation
\[ \text{Molarity} = \frac{\text{Mass of solute}}{\text{Volume of solution in L}} \]
Step 2: Apply the given values and compute the molarity. Final Conclusion: The molarity is \( 1.25 \times 10^{-1} \).Top JEE Main Chemistry Questions
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