For a bulb of rating 4V, 6W, we can calculate the resistance using the formula: \[ P = \frac{V^2}{R} \] Thus, \( R = \frac{V^2}{P} = \frac{4^2}{6} = \frac{16}{6} \approx 2.67 \, \Omega \). Now, to operate safely with a 240V mains supply, the total resistance in the series connection must be: \[ R_{{total}} = \frac{V_{{total}}^2}{P_{{total}}} \] For total power 6W per bulb, and for the total power at 240V, the number of bulbs required can be calculated to be 40.
Thus, the correct answer is option (b).
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______. 
In the given circuit, the potential difference across the plates of the capacitor \( C \) in steady state is 
