The metal ion (in gaseous state) with lowest spin-only magnetic moment value is
- V2+
- Ni2+
- Cr2+
- Fe2+
The Correct Option is A
Solution and Explanation
The correct option is(B): Ni2+
| Valence shell Configuration | Unpaired electrons |
| V2+ → 3d34s0 | n = 3 |
| Ni2+ → 3d84s0 | n = 2 |
| Cr2+ → 3d44s0 | n = 4 |
| Fe2+ → 3d64s0 | n = 4 |
Since Ni2+ has least number of unpaired electrons. Hence Ni2+ will have lowest spin only magnetic moment Value.
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Concepts Used:
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