Question

The median of the frequency distribution is: \[ \begin{array}{c|cccc} x & 1 & 2 & 3 & 4\\ \hline f & 2 & 4 & 1 & 3 \end{array} \]

• A. 1
• B. 2
• C. 3
• D. 4

Hint:

Use cumulative frequency to quickly locate median position.

Answer 1

The Correct Option is B

Concept: Median is the middle value after arranging data.
Step 1: Total frequency.
\[ N = 2 + 4 + 1 + 3 = 10 \]
Step 2: Position of median.
\[ \frac{N}{2} = 5^{th} { and } 6^{th} { terms} \]
Step 3: Cumulative frequency.
\[ x=1 \rightarrow 2,\quad x=2 \rightarrow 6,\quad x=3 \rightarrow 7,\quad x=4 \rightarrow 10 \] The 5th and 6th terms lie in $x=2$.
Hence, the median is 2.