Step 1: Find the mean of the data.
Given observations are
\[
5,6,7,8,6,9,13,12,15
\]
Number of observations,
\[
n=9
\]
Sum of observations:
\[
5+6+7+8+6+9+13+12+15=81
\]
Therefore, mean is
\[
\bar x=\frac{81}{9}
\]
\[
\bar x=9
\]
Step 2: Find the absolute deviations from the mean.
Now compute \(|x_i-\bar x|\):
\[
|5-9|=4
\]
\[
|6-9|=3
\]
\[
|7-9|=2
\]
\[
|8-9|=1
\]
\[
|6-9|=3
\]
\[
|9-9|=0
\]
\[
|13-9|=4
\]
\[
|12-9|=3
\]
\[
|15-9|=6
\]
Step 3: Find the sum of absolute deviations.
\[
4+3+2+1+3+0+4+3+6
\]
\[
=26
\]
Step 4: Calculate mean deviation about the mean.
Mean deviation about the mean is given by
\[
\text{MD}=\frac{\sum |x_i-\bar x|}{n}
\]
Therefore,
\[
\text{MD}=\frac{26}{9}
\]
\[
=2.888\ldots
\]
\[
\approx 2.88
\]
Step 5: Final conclusion.
Hence, the mean deviation about the mean is
\[
\boxed{2.88}
\]