Question:

The mean deviation about the mean for the following data:
\[ 5,6,7,8,6,9,13,12,15 \] is

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Mean deviation about the mean is calculated by taking the average of absolute deviations from the arithmetic mean.
Updated On: Jun 15, 2026
  • \(1.55\)
  • \(2.88\)
  • \(3.89\)
  • \(5\)
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The Correct Option is B

Solution and Explanation

Step 1: Find the mean of the data.
Given observations are
\[ 5,6,7,8,6,9,13,12,15 \]
Number of observations,
\[ n=9 \]
Sum of observations:
\[ 5+6+7+8+6+9+13+12+15=81 \]
Therefore, mean is
\[ \bar x=\frac{81}{9} \]
\[ \bar x=9 \]

Step 2: Find the absolute deviations from the mean.
Now compute \(|x_i-\bar x|\):
\[ |5-9|=4 \] \[ |6-9|=3 \] \[ |7-9|=2 \] \[ |8-9|=1 \] \[ |6-9|=3 \] \[ |9-9|=0 \] \[ |13-9|=4 \] \[ |12-9|=3 \] \[ |15-9|=6 \]

Step 3: Find the sum of absolute deviations.
\[ 4+3+2+1+3+0+4+3+6 \]
\[ =26 \]

Step 4: Calculate mean deviation about the mean.
Mean deviation about the mean is given by
\[ \text{MD}=\frac{\sum |x_i-\bar x|}{n} \]
Therefore,
\[ \text{MD}=\frac{26}{9} \]
\[ =2.888\ldots \]
\[ \approx 2.88 \]

Step 5: Final conclusion.
Hence, the mean deviation about the mean is
\[ \boxed{2.88} \]
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