Question

The maximum number of RBr producing 2-methylbutane by above sequence is _____________.

• A. 3
• B. 5
• C. 4
• D. 6

Hint:

When working with Grignard reagents, consider all possible structural isomers that could lead to the desired product, taking into account the reaction conditions and the nature of the alkyl halides.

Answer 1

The Correct Option is A

The given reaction involves the alkylation of a halide (RBr) with magnesium in dry ether to form a Grignard reagent, which then reacts with water to produce 2-methylbutane. 

Considering the structural isomers of RBr, the maximum number of isomers that can produce 2-methylbutane in this reaction is 3. 

The possible isomers of RBr that would produce 2-methylbutane are: 
- 1-Bromo-3-methylbutane 
- 2-Bromo-2-methylbutane 
- 3-Bromo-2-methylbutane 

Hence, the maximum number of RBr producing 2-methylbutane is 3.