





(When G = EDG) (When G = EWG)
EDG → Electron donating group
EWG → Electron withdrawing group
So, the correct option is (A).
Consider the following reaction sequence.
Which of the following hydrocarbons reacts easily with MeMgBr to give methane? 
Proton (P) and electron (e) will have same de-Broglie wavelength when the ratio of their momentum is (assume mp = 1849me):
Hydrocarbons are organic compounds that are entirely made up of only two kinds of atoms – carbon and hydrogen. Typically, hydrocarbons are colourless gases that have very weak odours.
According to experimental evidences, SE (S = substitution; E = electrophilic) reactions are supposed to proceed via the following three steps: