The major product formed in the following reaction is :
$CH _{3} CH = CHCH \left( CH _{3}\right)_{2} \stackrel{ HBr }{\longrightarrow}$
- $CH _{3} CH _{2} CH _{2} C ( Br )\left( CH _{3}\right)_{2}$
- $\operatorname{Br}\left( CH _{2}\right)_{3} CH \left( CH _{3}\right)_{2}$
- $CH _{3} CH _{2} CH ( Br ) CH \left( CH _{3}\right)_{2}$
- $CH _{3} CH ( Br ) CH _{2} CH \left( CH _{3}\right)_{2}$
The Correct Option is A
Solution and Explanation
Top Questions on Alkenes
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The C--Cl bond is formed using \(sp^2\) hybridised orbital of carbon.
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Concepts Used:
Alkenes
Alkenes
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
IUPAC Nomenclature of Alkenes
- An alkene or cycloalkene is indicated by the suffix (ending) ene.
- For the root name, the longest chain must include both carbon atoms of the double bond.
- The root chain must be numbered beginning at the end closest to a double bond carbon atom. If the double bond is in the chain's centre, the nearest substituent rule is used to determine where the numbering begins.
- If the compound contains more than one double bond, it is named with a diene, triene, or equivalent prefix indicating the number of double bonds, and each double bond is assigned a locator number.
Read More: Unsaturated Hydrocarbon